Answer :
Answer:
5.08 metres
Explanation:
The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron
The two protons will exert a repulsive force of 0.5 N when they are at a distance of [tex]2.146625 \times10^{-14} \,m[/tex] away from each other.
As protons have very little mass the gravitational force will be negligible. So here we will consider the electrostatic force between them.
- According to Coulomb's law in electrostatics, the electrostatic force between two charges can be given by;
- [tex]F=k\frac{q_{1}q_{2} }{r^2}[/tex]
- Where [tex]k \approx 9 \times 10^9 \, Nm^2 /C^2[/tex]
- Here, since both the particles are protons;
- [tex]q_1 = q_2 = 1.6 \times 10^{-19}\,C[/tex]
- Given that F = 0.5 N
- Substituting the known values in the Coulomb's law equation, we get;
[tex]0.5\, N = 9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{r^2}[/tex]
ie; [tex]r= \sqrt{9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{0.5\, N} } = 2.146625 \times 10^{-14}\,m[/tex]
Learn more about Coulomb's Law here:
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