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The pressure of a gas is reduced from 1220 mmHg to 836 mmHg as the volume of its container is increased by moving a piston from 85 mL to 350 mL. What would the final temperature (in Kelvin) be if the original temperature was 363 K?

Answer :

asuwafohjames

Answer:

1024.24 K

Explanation:

From the question,

Applying the general gas eqaution

PV/T = P'V'/T'.................... Equation 1

Where P, V, and T = Initial pressure, initial volume and initial Temperature of the gas respectively,  P', V' and T' = Final pressure, Final Volume and Final temperature of the gas respectively

make T' the subject of the equation

T' = P'V'T/(PV).................... Equation 2

Given: P = 1220 mmHg, V = 85 mL, P' = 836 mmHg, V' = 350 mL, T = 363 K

Substitute these value into equation 2

T' = (836×350×363)/(1220×85)

T' = 1024.24 K

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