Answer :
Answer: The volume for this gas is 0.732 L.
Explanation:
Given : No. of moles = 0.582 mol
Temperature = [tex]15^{o}C = (15 + 273) K = 288 K[/tex]
Pressure = 18.8 atm
Using the ideal gas equation, volume for the given gas is calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula.
[tex]PV = nRT\\18.8 atm \times V = 0.582 mol \times 0.0821 L atm/mol K \times 288 K\\V = \frac{0.582 mol \times 0.0821 L atm/mol K \times 288 K}{18.8}\\= \frac{13.761}{18.8}\\= 0.732 L[/tex]
Therefore, it can be concluded that the volume for this gas is 0.732 L.