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A birthday balloon is filled with 6.4 L of Helium. The pressure changes to 0.87 atm and the balloon expands to occupy a volume of 20.5 L. What was the initial pressure exerted on the balloon in psi?

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Answer :

Stephen46

Answer:

3.97 psi

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we're finding the new pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

We have

[tex]P_2 = \frac{6.4 \times 0.87}{20.5} = \frac{5.568}{20.5} \\ = 0.2716.... \\ \\ = 0.27 \: \: \: atm[/tex]

But

1 atm = 14.7 psi

Then 0.27 atm =

[tex] \frac{14.7 \times 0.27}{1} = 3.969 \\ [/tex]

We have the final answer as

3.97 psi

Hope this helps you

Answer:

3.97 psi

Explanation:

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