Answer :
Answer:
P = 24.32 W
Explanation:
The question is, "Two resistors 5 Ω and 10 Ω are connected in parallel with a 9 V power supply. Calculate the output power of the power supply.".
The voltage of the power supply, V = 9 V
Resistor 1, R₁ = 5 Ω
R₂ = 10 Ω
The equivalent of parallel combination of resistors is given by :
[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_{eq}}=\dfrac{1}{5}+\dfrac{1}{10}\\\\R_{eq}=3.33\ \Omega[/tex]
The power of the output is given by :
[tex]P=\dfrac{V^2}{R_{eq}}\\\\=\dfrac{9^2}{3.33}\\\\P=24.32\ W[/tex]
So, the output power is equal to 24.32 W.