Answer :
Answer:
[tex] {x}^{2} + 2x - 8 \\ sum = 2 \: and \: product = - 8 \\ factors = 4 \: and \: - 2 \\ = > {x}^{2} + 4x - 2x - 8 \\ = x(x + 4) - 2(x + 4) \\ = (x - 2)(x + 4)[/tex]
Answer:
[tex] {x}^{2} + 2x - 8 \\ sum = 2 \: and \: product = - 8 \\ factors = 4 \: and \: - 2 \\ = > {x}^{2} + 4x - 2x - 8 \\ = x(x + 4) - 2(x + 4) \\ = (x - 2)(x + 4)[/tex]