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The ordered pair below is a solution to which equation? (2, 12) A.y=1/5x B.y=1/2x C. y = 2x D. y = 6x

Answer :

D. y = 6x...subbing in (2,12)...x = 2 and y = 12
    12 = 6(2)
    12 = 12 (correct)

so (2,12) is a solution to : y = 6x
carlos2112

Answer:

D. y = 6x

Step-by-step explanation:

In order to conclude which pair is a real solution to one of these equations, we need to evaluate the point in each equation.

Let:

[tex](x,y)=(2,12)[/tex]

So, this pair will be a solution if when evaluating the value of x=2 in the function the result is y=12.

For A.

[tex]y(x)=\frac{1}{5}x \\\\y(2)=\frac{2}{5} =0.4\neq12[/tex]

This pair is not a solution to this equation.

For B.

[tex]y(x)=\frac{1}{2}x\\\\y(2)=\frac{2}{2} =1 \neq 12[/tex]

This pair is not a solution to this equation.

For C.

[tex]y(x)=2x\\\\y(2)=2*2=4 \neq 12[/tex]

This pair is not a solution to this equation.

For D.

[tex]y(x)=6x\\\\y(2)=6*2=12[/tex]

This pair is a solution to this equation.

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