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Today at 6:40 AM
Mathematics

Answered

What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = -1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = 1

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = 1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = -1

Answer :

Nirina7 Nirina7

Today at 6:45 AM

the unique answer is A
sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = -1

(just put the Θ in the trigonometry circle)

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