Answer:
Acceleration, [tex]a=4.83\ m/s^2[/tex]
Explanation:
It is given that,
Mass of the meteor, m = 521 kg
Force acting on the meteor, F = 2520 N
Let a is the acceleration of the meteor. It can be calculated using the Newton's second law of motion. According to this law the force acting on an object is equal to the product of mass and acceleration with which it is moving. Mathematically, it is given by :
[tex]F=m\times a[/tex]
[tex]a=\dfrac{F}{m}[/tex]
[tex]a=\dfrac{2520\ N}{521\ kg}[/tex]
[tex]a=4.83\ m/s^2[/tex]
So, the acceleration of the meteor is [tex]4.83\ m/s^2[/tex]. Hence, this is the required solution.
