d=10
Answer:
Solution given:
[tex]\sqrt{25+3x}=d+2x[/tex]
squaring both side
25+3x=(d+2x)²
when x=-3
25+3*-3=(d+2*-3)²
25-9=(d-6)²
16=(d-6)²
[tex]\sqrt{16}=d-6[/tex]
4=d-6
d=4-6
d = 6
Step-by-step explanation:
[tex] \sqrt{25 + 3( - 3)} = d + 2( - 3) \\ 4 = d - 6 \\ d = 10[/tex]
hopefully this makes sense
:)
