Answer :
Explanation:
The given chemical equation is:
[tex]2A + 4B -> 2C + 2D[/tex]
The rate of the reaction is 0.0352 M/s.
During the course of the reaction, the rate of reactants decreases, and the rate of products increases.
The rate of disappearance of B is shown below:
[tex]rate=-\frac{1}{4} \frac{d[B]}{dt}[/tex]
So, rate of change of B is :
[tex]rate of change of B =- rate * 4\\=-0.0352 M/s * 4\\=-0.1408M/s\\\\=-0.141M/s[/tex]
Option C.
In the given reaction, rate of change of reactant B is equal to -0.141 M/s.
What is the rate of reaction?
Rate of any chemical reaction defines the speed of the completion of that reaction.
In the question given reaction is:
2A + 4B ----> 2C + 2D
Rate of reaction = 0.0352 M/s.
Rate of the reaction with respect to the reactant B is written as:
Rate = [tex]${\rm{ - }}\frac{{\rm{1}}}{{\rm{4}}}\frac{{\left[ {{\rm{dB}}} \right]}}{{{\rm{dT}}}}$[/tex], where negative sign shows the disappearance of reactant B.
Rate of change of B i.e. [tex]$\frac{{{\rm{dB}}}}{{{\rm{dT}}}}$[/tex] = 4 × (-rate)
[tex]$\frac{{{\rm{dB}}}}{{{\rm{dT}}}}$[/tex] = 4 × (-0.0352) = -0.1408 = -0.141 M/s
Hence, -0.141 M/s is the rate of change of B.
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