Answer:
38°
Step-by-step explanation:
90-58
I'm unsure if that's right but i think it is. otherwise 180-58 but angle x should be the rest of the angle in KAI
Answer:
[tex]\boxed{\boxed{\tt \angle x=32^{\circ}}}[/tex]
Step-by-step explanation:
From the diagram given, we know that ∠BAC and ∠IAK are vertical angles.
*Vertical angles are two lines that intersect each other.*
So ∠BAC is equal to ∠IAK.
[tex]\tt \overline{KL} \perp \overline{FG}[/tex] so, ∠ABC =90°
(Interior angles in a triangle always add up to 180°).
[tex]\tt \angle BAC+\angle ABC+\angle BCA=180^{\circ}[/tex]
[tex]\tt 58+90+\angle BCA=180^{\circ}[/tex]
[tex]\tt \angle BCA=32^{\circ}[/tex]
∠BCA and ∠x are vertical angles, therefore they are congruent.
∠BCA and ∠x= 32°