Answer :
Answer: True
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Explanation:
If you meant to say [tex]f(x) = \frac{2x+3}{x^2-4}[/tex], then we cannot have x^2-4 equal to 0
We can never have 0 in the denominator.
Set the expression equal to 0 and solve for x
x^2 - 4 = 0
(x-2)(x+2) = 0 .... difference of squares rule
x-2 = 0 or x+2 = 0
x = 2 or x = -2
So if either x = 2 or x = -2, then we have x^2-4 equal to zero.
So these are the values we must kick out of the domain to avoid a division by zero error.
In short, the restrictions for x are 2 and -2. That's why the statement is true.