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Diseases I and II are prevalent among people in a certain population. It is assumed that 11% of the population will contract disease I sometime during their lifetime, 16% will contract disease II eventually, and 2% will contract both diseases. (a) Find the probability that a randomly chosen person from this population will contract at least one disease. .25 Correct: Your answer is correct. (b) Find the conditional probability that a randomly chosen person from this population will contract both diseases, given that he or she has contracted at least one disease. (Round your answer to four decimal places.)

Answer :

okpalawalter8

Answer:

a)  [tex]P(A \cup B)=0.23[/tex]

b)  [tex]P(X)=0.87[/tex]

Step-by-step explanation:

From the question we are told that:

Probability of contacting disease 1 [tex]P(1)=0.11[/tex]

Probability of contacting disease 2 [tex]P(2)=0.16[/tex]

Probability of contacting both disease  [tex]P(1\& 2)=0.2[/tex]

a)

Generally the equation for a Random contact is mathematically given by

[tex]P(A \cup B)=P(1)+P(2)-P(A \cap B)[/tex]

[tex]P(A \cup B)=\frac{11}{100}+\frac{16}{100}-\frac{4}{100}[/tex]

[tex]P(A \cup B)=\frac{11+16-4}{100}[/tex]

[tex]P(A \cup B)=0.23[/tex]

b)

Generally the equation for Probability of contacting both after having contacted one is mathematically given by

[tex]P(X)=\frac{P(1\& 2)}{P(A \cup B)}[/tex]

Therefore

[tex]P(X)=\frac{0.2}{0.23}[/tex]

[tex]P(X)=0.87[/tex]

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