Using weighed averages, it is found that:
- The final grade is 91.
- The final grade is 66.8.
- The higher grade would be 79.55, with the second grading scheme.
- On average, she sold $48,280 per day.
- On average, she makes $12.5 per hour.
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To find the weighed average, we multiply each value by it's weight.
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Question 1:
- Grade of 91, with a weight of 67%.
- Grade of 91, with a weight of 33%.
Thus:
[tex]F = 91\times0.67 + 91\times0.33 = 91[/tex]
The final grade is 91.
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Question 2:
- Grade of 83, with a weight of 40%(highest grade).
- Grade of 60, with a weight of 30%.
- Grade of 52, with a weight of 30%.
Thus:
[tex]F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8[/tex]
The final grade is 66.8.
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Question 3:
With teacher 1:
- 75 with a weight of 25%.
- 80 with a weight of 10%.
- 85 with a weight of 40%.
- 62 with a grade of 25%.
Thus:
[tex]F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25[/tex]
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With teacher 2:
- 75 with a weight of 15%.
- 80 with a weight of 10%.
- 85 with a weight of 60%.
- 62 with a weight of 15%.
Thus:
[tex]F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55[/tex]
The higher grade would be 79.55, with the second grading scheme.
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Question 4:
- Average of $36,432, with a weight of [tex]\frac{3}{3+10} = \frac{3}{13}[/tex]
- Average of $51,834, with a weight of [tex]\frac{10}{13}[/tex]
Thus:
[tex]A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280[/tex]
On average, she sold $48,280 per day.
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Question 5:
- Average of $14.84, with a weight of [tex]\frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}[/tex]
- Average of $10.76, with a weight of [tex]\frac{4}{7}[/tex]
Thus:
[tex]A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5[/tex]
On average, she makes $12.5 per hour.
A similar problem is given at https://brainly.com/question/24398353