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MATH PLZ HELP

2. Write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(2,-1) ; y = 3/2x + 6
A. y = -3/2x + 1
B. y = -3/2x - 1
C. y = -3/2x + 2
D. y = -3/2x + 4

Answer :

texaschic101
y = 3/2x + 6....slope here is 3/2.A parallel line will have the same slope.

y = mx + b
slope(m) = 3/2
(2,-1)...x = 2 and y = -1
now we sub and find b, the y int
-1 = 3/2(2) + b
-1 = 3 + b
-1 - 3 = b
-4 = b
so ur parallel line is : y = 3/2x - 4

u sure u wrote this question correctly ??

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