lexied2303
Answered

Graph the function represented in the table on the coordinate plane.

PLEASE HELP!!



(x) -2, -1, 0, 1, 2

(Y) -3, -1, 1, 3, 5

Graph the function represented in the table on the coordinate plane.PLEASE HELP!! (x) -2, -1, 0, 1, 2 (Y) -3, -1, 1, 3, 5 class=

Answer :

I hope this helps you
${teks-lihat-gambar} Аноним
InesWalston

Answer:

[tex]2x-y+1=0[/tex]

Step-by-step explanation:

The given points are,

[tex](-2,-3),(-1,-1),(0,1),(1,3),(2,5)[/tex]

The difference in x coordinates is 1 and the difference in y coordinates is also 1. As change in both x and y are same and constant, so graph will be a straight line.

Plotting the points on the Cartesian coordinates, we get a straight line.

Applying two point formula, taking (-2,-3), (-1,-1), we get

[tex]\Rightarrow \dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}[/tex]

[tex]\Rightarrow \dfrac{y+3}{-1+3}=\dfrac{x+2}{-1+2}[/tex]

[tex]\Rightarrow \dfrac{y+3}{2}=\dfrac{x+2}{1}[/tex]

[tex]\Rightarrow y+3=2(x+2)[/tex]

[tex]\Rightarrow y+3=2x+4[/tex]

[tex]\Rightarrow 2x-y+1=0[/tex]

${teks-lihat-gambar} InesWalston

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