Answer :

diene
[tex]\text{2LiI(s)}\rightarrow \text{2Li(s)+}\text{I}_{2}\text{(s)}[/tex]
MissPhiladelphia
Solid lithium iodide decomposes into solid lithium and iodine gas. To write the reaction, we need to know the formula of the elements involved. It is follows:

Lithium = Li
Iodide = I
Lithium iodide = LiI

2LiI = 2Li + I2

Hope this answers the question. Have a nice day.

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