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a ladybug sits at the outer edge of a merry-go-round and a gentleman bug sits halfway between her and the axis of rotation. The merry-go-round makes a complete revolution once each second. What is the gentleman bug's angular speed?

Answer :

Sanarah
The gentleman bug's angular speed is the same as the ladybug's (1 rev/s)
Lanuel

The gentleman bug's angular speed is the same as the angular speed of the ladybug.

What is angular speed?

Angular speed can be defined as the rate of change of angular displacement of an object with respect to time. Thus, it is a measure of how fast and quickly an object revolves (rotates) relative to another point or how its angular position changes with respect to time.

The formula for angular speed.

Mathematically, angular speed is given by this formula:

[tex]\omega = \frac{\Delta \theta}{\Delta t}[/tex]

Where:

  • [tex]\Delta \theta[/tex] is the change in angular displacement.
  • [tex]\Delta t[/tex] is the change in time.

Note: The angular speed is generally the same at every point on the merry-go-round, whether they are sitting at the outer edge, halfway or the axis of rotation.

Read more on angular speed here: https://brainly.com/question/6860269

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