aguilera102
Answered

Consider the following equilibrium system: 3O2(g)  2O3(g); Keq = 1 Which equation compares the concentration of oxygen and ozone?

A. [O2]3 = [O3]2

B. [O2] = [O3]

C. [O2] = [O3]3/2

D. [O2]2 = [O3]3

Answer :

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

 3O2(g) <--> 2O3(g); 

Keq = 1 = [O3]^2/[O2]^3 

So [O2]^3 = [O3]^2 

Thus A) is correct

Answer: [tex][O_2]^3=[O_3]^2[/tex]

Explanation: Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

For the given reaction:

[tex]3O_2(g)\rightleftharpoons 2O_3(g)[/tex]

[tex]K_{eq}=\frac{[O_3]^2}{[O_2]^3}[/tex]

Given :[tex]K_{eq}=1[/tex]

Thus [tex]1=\frac{[O_3]^2}{[O_2]^3}[/tex]

[tex][O_2]^3=[O_3]^2[/tex]

Other Questions