Answer :
Step by step is like....:
(3x2+2x−3)(x−1)
=(3x2+2x+−3)(x+−1)
=(3x2)(x)+(3x2)(−1)+(2x)(x)+(2x)(−1)+(−3)(x)+(−3)(−1)
=3x3−3x2+2x2−2x−3x+3
=3x3−x2−5x+3
Hoped I helped!
(3x2+2x−3)(x−1)
=(3x2+2x+−3)(x+−1)
=(3x2)(x)+(3x2)(−1)+(2x)(x)+(2x)(−1)+(−3)(x)+(−3)(−1)
=3x3−3x2+2x2−2x−3x+3
=3x3−x2−5x+3
Hoped I helped!