If the function f' has a continuous derivative on [0, c] then integral from 0 to c f"(x)dx=
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The result follows from the fundamental theorem of calculus. Since [tex]f''(x)[/tex] is the derivative of [tex]f'(x)[/tex], we have
[tex]\displaystyle \int_0^c f''(x) \, dx = \boxed{f'(c) - f'(0)}[/tex]
(E)