Answer :
Answer:
[tex]\huge\boxed{\sf x\leq 2}[/tex]
Step-by-step explanation:
Given inequality:
[tex]56-10x\geq 20+8x\\\\Subtract \ 20 \ from \ both \ sides\\\\56-20-10x\geq 8x\\\\36-10x\geq 8x\\\\Add \ 10x \ to \ both \ sides\\\\36\geq 8x+10x\\\\36\geq 18x\\\\Divide \ 18 \ to \ both \ sides\\\\2 \geq x\\\\OR\\\\x\leq 2\\\\\rule[225]{225}{2}[/tex]
[tex]\bf{56-10x\geq 20+8x }[/tex]
Subtract 8x on both sides.
[tex]\bf{56-10x-8x\geq 20 }[/tex]
Combine −10x and −8x to get −18x.
[tex]\bf{56-18x\geq 20 }[/tex]
Subtract 56 from both sides.
[tex]\bf{-18x\geq 20-56 }[/tex]
Subtract 56 from 20 to get −36.
[tex]\bf{-18x\geq -36 }[/tex]
Divide both sides by −18. Since −18 is <0, the inequality direction is changed.
[tex]\bf{x\leq \dfrac{-36}{-18} }[/tex]
Divide −36 by −18 to get 2.
[tex]\bf{x\leq 2 \ \ \to \ \ \ Answer}[/tex]
We conclude that the correct option is "C".