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Car A starts from rest at t = 0 and travels along a straight road with a constant acceleration of 6 ft/s2 until it reaches a speed of 80 ft/s. Afterwards it maintains this speed. Also, when t = 0, car B located 6000 ft down the road is traveling towards A at a constant speed of 60 ft/s. Determine the distance traveled by car A when they pass each other.

Answer :

onyebuchinnaji

The distance traveled by car A when they pass each other is 3,428.56 ft.

Time when the two cars pass each other

(Va)t - (Vb)t = d

where;

  • Va is speed of car A
  • Vb is speed of car B
  • t is time when they pass each other
  • d is the distance between them

80t - (-60)t = 6000

80t + 60t = 6000

140t = 6000

t = 6000/140

t = 42.857 s

Distance traveled by car at the calculated time

s = vt

s = 80 x 42.857

s = 3,428.56 ft

Thus, the distance traveled by car A when they pass each other is 3,428.56 ft.

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