If you apply the changes below to the quadratic parent function, f(x) = x²
what is the equation of the new function?
• Shift 3 units right.
• Vertically stretch by a factor of 4.
• Reflect over the x-axis.
A. g(x) = -4(x+3)²
B. g(x) = -4(x-3)²
C. g(x) = (-4x - 3)²
D. g(x) = 4x²+3

Answer :

The equation of the unique function exists g(x) = -4(x-3)².

What is a quadratic equation?

The polynomial of degree two exists named a quadratic polynomial and the equation corresponding to a quadratic polynomial P(x) exists named a quadratic equation.

Given: F(x) = x²

The vertical stretch by a factor of 4 exists can be satisfied by (b)

if we use a vertical stretch, it transforms the y-values which causes it to seem skinnier when graphed.

Multiply 4 by f(x) which provides 4x².

As the reflection over the x-axis, so multiply it by -1 to f(x), which results in -4x².

Shift the graph right 3 which exists by moving it right, so by adjusting the x values indicating use f(x-3), to obtain this subtract the value from x when you move right, and add the value to x when you move left.

Hence, the unique graph would be g(x) = -4(x-3)²

Therefore, the correct answer is option B. g(x) = -4(x-3)².

To learn more about  equations refer to:

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