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The middle 50% of the training times of which person had the least spread? Explain how you know.

(times are in seconds)

The middle 50% of the training times of which person had the least spread? Explain how you know. (times are in seconds) class=

Answer :

Due to the lower value of the interquartile range, it is found that the training times of Miguel had the least spread.

What are the median and the quartiles of a data-set?

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference of the third quartile by the first quartile of the data-set.

The ordered data-set for Adam is given by:

91, 92, 97, 98, 100, 101, 103, 104, 105, 106.

Hence:

  • The first half is 91, 92, 97, 98, meaning that the first quartile is (92 + 97)/2 = 94.5.
  • The second half is 103, 104, 105, 106, meaning that the third quartile is (104 + 105)/2 = 104.5.

Hence the IQR is:

104.5 - 94.5 = 10.

The ordered data-set for Miguel is given by:

85, 86, 88, 89, 92, 93, 94, 96, 97, 100.

Then:

  • The first half is 85, 86, 88, 89, meaning that the first quartile is (86 + 88)/2 = 87.
  • The second half is 94, 96, 97, 100, meaning that the third quartile is (96 + 97)/2 = 96.5.

The IQR is:

96.5 - 87 = 9.5.

Due to the lower value of the interquartile range, it is found that the training times of Miguel had the least spread.

More can be learned about the interquartile range at https://brainly.com/question/17083142

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