Answer :

shaikhmohd0119

grams of radium can form by passing 235 C through an electrolytic cell containing a molten radium salt is  0.2752 g

Given

  The balanced half-reaction is,

    Ra⁺²(aq) + 2e⁻ → Ra (s)

Now given Coloumb of charge = 235 C

1 Mole of     Ra⁺² contains charge of 2 Faraday

hence

  1 Mole of     Ra⁺² = 2 Faraday

                         = 2× 96485 C

                         = 192970 C

So,

192970 C= 1 Mole of Ra⁺²

1 C = [tex]\frac{1}{192970}[/tex] mole of Ra⁺²

     = 5.1821 × 10⁻⁶ mole of Ra⁺²

235 C = 5.1821 × 10⁻⁶  × 235 mole of Ra⁺²

           = 0.0012178 mole of Ra⁺²

Mass of Ra⁺²   = 0.0012178 × 226.025 g

                        = 0.2752 g

Thus from the above conclusion we can say that grams of Ra that formed by passing 235C through an electrolytic cell containing a molten radium salt is   0.2752 g .

Learn More about Electrolysis here : brainly.com/question/14964810

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