Answered

How many seconds does it take to deposit 1.63 g of Ni on a decorative drawer handle when 13.7 A is passed through a Ni(NO₃)₂ solution?

Answer :

The time taken to deposit 1.63 g of Ni is 391 seconds.

How to find the number of moles ?

The number of moles of Ni deposited is:

Moles = [tex]\frac{1.63}{58.69}[/tex]

          = 2.77 × 10⁻² mol Ni

Half reaction for Ni⁺² is:

Ni⁺² + 2e⁻ → Ni

Thus, for every mole of Ni, we need 2 moles of electrons.

Therefore, Number of moles of electron is:

2 × (2.77 × 10⁻²) = 5.55 × 10⁻² mole⁻

Charge = Moles × Faraday constant

            = 5.55 × 10⁻² × 96485 = 5358.7 C

Thus, time taken is:

Time = Charge/Current

[tex]Time = \frac{5358.7}{13.7} = 391 sec[/tex]

Thus from the above conclusion we can say that The time taken is 391 seconds.

Learn more about Faraday constant here:

https://brainly.com/question/15583306

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