Answer :
first term = 4
second term = 4x2=8
3rd = 8x2 =16
4th = 16x2 = 32
5th = 32x2=64
6th = 64x2 = 128
answer: first term = 4
second term = 4x2=8
3rd = 8x2 =16
4th = 16x2 = 32
5th = 32x2=64
6th = 64x2 = 128
answer: first term = 4
common ratio mean geometric sequence
[tex]a_n=a_1(r)^{n-1}[/tex]
given tat r=2
and a6=128
[tex]a_6=a_1(2)^{6-1}=128[/tex]
[tex]128=a_1(2)^{5}[/tex]
[tex]128=a_1(32)[/tex]
divide both sides by 32
[tex]4=a_1[/tex]
the first term is 4
[tex]a_n=a_1(r)^{n-1}[/tex]
given tat r=2
and a6=128
[tex]a_6=a_1(2)^{6-1}=128[/tex]
[tex]128=a_1(2)^{5}[/tex]
[tex]128=a_1(32)[/tex]
divide both sides by 32
[tex]4=a_1[/tex]
the first term is 4