Answer :
The empirical formula is C6H8O7.
What is an empirical formula?
A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms, is known as empirical formula.
This can be done by calculating molar ratio of elements using masses and molar masses of the element.
Mass of Carbon (C) in given compound is= 37.51g
Mass of Hydrogen (H) in the given compound is= 4.20g
Mass of Oxygen (O) in given compound is= 58.29g
Molar mass of C = 12.0107g
Molar mass of H = 1.00784g
Molar mass of O = 15.999g
by diving the mass of elements with their respective molar masses we get the number of moles of elements:
no. of moles of C= 37.51/12= 3.123moles
no. of moles of H= 4.20/1.00784 =4.167moles
no. of moles of O = 58.29/15.999 = 3.643moles
The Molar ratio of elements/atoms can be obtained by diving the above number of moles with the lesser number of moles in the above three,
C= 3.123/3.123
H= 4.167/3.123
O= 3.653/3.123
By multiplying each ratio with '6' we get the whole number.
C= 1*6
H= 1.334*6
O= 1.166*6
The empirical formula is= C6H8O7.
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The empirical formula is [tex]C_{6} H_{8} O_{7}[/tex].
What is an empirical formula in chemistry?
The relative atomic ratios in a compound are given by an empirical formula.
The chemical formula of a compound that gives the proportions (ratios) of the elements present in the complex but not the precise number or arrangement of atoms is known as an empirical formula.
This would be the compound's element-to-whole number ratio with the lowest value.
The ratios also hold true at the molar level.
Eg: The chemical structure of glucose is C6H12O6. Every mole of carbon and oxygen is accompanied by two moles of hydrogen. Glucose has the empirical formula CH2O.
Ribose has the chemical formula C5H10O5, which can be simplified to the empirical formula CH2O.
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