use each graph to determine an equation of the circle in (a) center radius form and (b) general form

(x -3)² +(y -1)² = 4 . . . . center-radius form
x² +y² -6x -2y +6 = 0 . . . . general form
The "center-radius" form is ...
(x -h)² +(y -k)² = r² . . . . . . . circle with center (h, k) and radius r
The graphed circle has its center at (3,1) and a radius of 2. Putting these numbers into the above form gives the equation ...
(x -3)² +(y -1)² = 4 . . . . center-radius form
Expanding the parentheses, we get ...
x² -6x +9 +y² -2y +1 = 4
Subtracting 4, and putting in general form, the equation becomes ...
x² +y² -6x -2y +6 = 0 . . . . general form
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