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a race car starts from rest and travels east along a straight and level track. for the first 5.0 s of the car's motion, the eastward component of the car's velocity is given by vx(t)

Answer :

The acceleration is aₓ = 7.54 m/s².

How to find the acceleration?

The rate at which an item changes its velocity is known as the vector quantity known as acceleration.

When an object's velocity changes, it is said to be accelerating.

uₓ(t) = (0.980 m/s³) t²

The time-dependent derivative of velocity is acceleration.

aₓ(t) = 2 (0.980 m/s³) t

aₓ(t) = (1.96 m/s³) t

When,

uₓ = 14.5 m/s, the time is:

14.5 m/s = (0.980 m/s³) t²

t = 3.85 s

Connecting to the acceleration equation,

aₓ = (1.96 m/s³) (3.85 s)

aₓ = 7.54 m/s²

To learn more about acceleration, refer

https://brainly.com/question/18608559

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