Answered

Three orders are placed at a sandwich shop. Four sandwiches, two beverages, and
one salad costs $40; two sandwiches, one beverage, and two salads costs $26; and
three sandwiches, three beverages, and two salads costs $38. How much does each
item cost?

Answer :

okpalawalter8

The respective prices are given below as

The price of the sandwich is 20/3 dollars.

The salad may be purchased for a price of $16/3.

There is a fee of $2 for the drinks.

How can you build equations that are simultaneous?

Let's say that the price of the sandwich is x.

Allow the price of salad to equal y.

Allow the price of drinks to equal z.

The new total for this meal is $46. It includes three sandwiches, three beers, and two salads. Thus;

3x + 3y + 2z = 40 ——- (eq 1)

The price of $29 covers two sandwiches, two drinks, and one salad.

Thus;

2x + 2y + z = 26 ——-(eq 2)

It will cost you $54 for four sandwiches, one drinks, and three salads. Thus;

4x + y + 3z = 38 ———-(eq 3)

The following are the results of concurrently solving the three equations:

x = 20/3

y = 16/3

z = 2

Therefore, the following is how much each item costs:

There is a charge of $20/3 for the sandwich.

The salad may be purchased for a price of $ 16/3.

There is a fee of $2 for the drinks.

You may get further information on simultaneous equations at the following link:

brainly.com/question/148035

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