Answer :
The class interval width for the distribution that we have here is given as $30000. The six midpoints and the class boundaries have being calculated below.
How to solve for the class boundary
238,000 - 58,000= 180000
180000 / 6 = 30000
Class Boundaries
1 58000 but less than 88,000
2 88,000 but less than 118,000
3 118,000 but less than 148,000
4 148,000 but less than 178,000
5 178,000 but less than 208,000
6 208,000 but less than 238,000
What is the class interval width?
238,000 - 58,000= 180000
180000 / 6 = 30000
width = 30000
The six class midpoints
- 58000 + 88000 / 2 = 73000
- 88000 + 118000 / 2 = 103,000
- 118000 + 148000 / 2 = 133,000
- 148000 + 178000 / 2 = 163000
- 178000 + 208000 / 2 = 193000
- 208000 + 238000 / 2 = 223000
Read more on class intervals here;
https://brainly.com/question/28183595
#SPJ1