Answer :
y=mx+b
m=slope
b=yint
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
given
(-1,3) and (2,-3)
slope=(-3-3)/(2-(-1))=(-6)/(2+1)=-6/3=-2
y=2x+b
find b
(-1,3) is a point
when x=-1, y=3
3=2(-1)+b
3=-2+b
add 2
5=b
y=2x+5
m=slope
b=yint
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
given
(-1,3) and (2,-3)
slope=(-3-3)/(2-(-1))=(-6)/(2+1)=-6/3=-2
y=2x+b
find b
(-1,3) is a point
when x=-1, y=3
3=2(-1)+b
3=-2+b
add 2
5=b
y=2x+5