Answer :
Answer:
Probability that neither of the two persons has a license = 3/28
Explanation:Total number of people fishing, n(Total) = 8
Number of people with fishing licenses, n(License) = 5
Number of people without fishing license, n(No license) = 3
Number of ways of choosing 2 people out of 8
[tex]\begin{gathered} 8C2=\frac{8!}{(8-2)!2!} \\ 8C2\text{ = }\frac{8!}{6!2!} \\ 8C2=\frac{8\times7\times6!}{6!\times2\times1} \\ 8C2=28\text{ ways} \end{gathered}[/tex]Since neither of the two people chosen has a license, they will be chosen from the 3 people who do not have a license
[tex]\begin{gathered} 3C2=\frac{3!}{(3-2)!2!} \\ 3C2=\frac{3\times2\times1}{2\times1} \\ 3C2=3\text{ ways} \end{gathered}[/tex]Probability that neither of the two persons has a license = 3/28