Answer :
Given:
The magnetic field is B = 0.2 T
The angle is
[tex]\theta\text{ = 30}^{\circ}[/tex]The speed of the helical path is
[tex]v\text{ = 3}\times10^7\text{ m/s}[/tex]To find the pitch.
Explanation:
The pitch can be calculated by the formula
[tex]P=\frac{2\pi m}{Bq}vcos\theta[/tex]Here, m is the mass of the electron whose value is 9.1 x 10^(-31) kg
q is the charge of the electron whose value is 1.6 x 10^(-19) C
On substituting the values, the pitch will be
[tex]\begin{gathered} P=\text{ }\frac{2\times3.14\times9.1\times10^{-31}\times3\times10^7\times cos\text{ 30}^{\circ}}{0.2\times1.6\times10^{-19}} \\ =\text{ 4.639}\times10^{-3}\text{ m} \end{gathered}[/tex]