Answer :

[tex]\begin{gathered} \sin 60^{\circ}=\frac{10\sqrt[]{3}}{x} \\ \frac{\sqrt[]{3}}{2}=\frac{10\sqrt[]{3}}{x} \\ x=20 \\ \text{now, } \\ \cos 60^{\circ}=\frac{x}{y} \\ \frac{1}{2}=\frac{20}{y} \\ y=40 \end{gathered}[/tex]

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