Answer :

Given:

[tex]\sqrt{14x^3}\text{ }\div\sqrt{7x}[/tex]

Required:

To calculate which option is correct

Explanation:

[tex]\begin{gathered} \sqrt{14x^3}\text{ }\div\sqrt{7x}\text{ \lparen x>0\rparen} \\ \\ \sqrt{\frac{14x^3}{7x}\text{ }}\text{ }\sqrt{a\text{ }}\text{ }\div\sqrt{b}\text{ =}\sqrt{\frac{a}{b}} \\ \\ \sqrt{2x^2} \\ \\ x\sqrt{2} \\ \end{gathered}[/tex]

Required answer:

Option D

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