Answer :
we have
[tex]c^{(-4)}\cdot c^{(-2)}[/tex]Applying the laws of exponent
in a multiplication, adds the exponents
so
[tex]\begin{gathered} c^{(-4-2)} \\ c^{(-6)}=\frac{1}{c^6} \end{gathered}[/tex]
we have
[tex]c^{(-4)}\cdot c^{(-2)}[/tex]Applying the laws of exponent
in a multiplication, adds the exponents
so
[tex]\begin{gathered} c^{(-4-2)} \\ c^{(-6)}=\frac{1}{c^6} \end{gathered}[/tex]