Isosceles triangle RST is inscribed in circle P. The measure of arc RT is 130°. What is the measure, in degrees, of ZSRT ?PLEASE HELP!!!!!

We have an isosceles triangle therefore
arc RT = arc RS =130°
In a circle we have 360°, so we can find arc ST with the next equation
arc ST= 360-130-130=100°
Then in order to find the m
[tex]\begin{gathered} m<\text{SRT}=\frac{1}{2}ST \\ m<\text{SRT}=\frac{1}{2}(100) \\ m<\text{SRT}=50\text{ \degree} \end{gathered}[/tex]