Answer :
the answer is 62 degrees
m[tex]\begin{gathered} 28+m<\text{FEH}=90 \\ m<\text{FEH}=90-28 \\ <\text{FEH}=62^0 \end{gathered}[/tex]
the answer is 62 degrees
m[tex]\begin{gathered} 28+m<\text{FEH}=90 \\ m<\text{FEH}=90-28 \\ <\text{FEH}=62^0 \end{gathered}[/tex]