The perimeter of a triangle is 93 ft. Side A of thetriangle is twice as long as side B. Side c is 3 ftlonger than side A. Find the length of each side.

Answer :

The perimeter P of a triangle is;

[tex]\text{Side A + Side B + Side C}[/tex]

Let side A be a. side B be b and side C be c;

[tex]\begin{gathered} a=2b \\ c=3+a=3+2b \end{gathered}[/tex][tex]\text{Perimeter P= 93ft}[/tex][tex]\begin{gathered} P=a+b+c \\ 93=2b+b+3+2b \\ 93-3=5b \\ 5b=90 \\ b=\frac{90}{5} \\ b=18ft \end{gathered}[/tex]

Then,

[tex]\begin{gathered} a=2b \\ a=2(18)_{} \\ a=36ft \end{gathered}[/tex]

So,

[tex]\begin{gathered} c=3+a \\ c=3+36 \\ c=39ft \end{gathered}[/tex]

The length of each of the sides is;

[tex]\begin{gathered} a=36ft \\ b=18ft \\ c=39ft \end{gathered}[/tex]