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In the following reaction, if there were 10 molecules of nitrogen gas (N2), howmany molecules of hydrogen gas (H2) and ammonia gas (NH3) would be presentin the reaction?N2 + 3H2+-> 2NH3N2 = 10; H2 = 30; NH3 = 20N2 = 10; H2 = 30; NH3 = 10N2 = 10; H2 = 800; NH3 = 700N2 = 10; H2 = 60; NH3 = 20

Answer :

To solve this question we have to use the ratios of the coefficients of the substances.

For hydrogen gas we have that per one molecule of nitrogen, 3 of hydrogen are used. If 10 molecules of nitrogen are used, then we have that:

[tex]10molN_2\cdot\frac{3molH_2}{molN_2}=30molH_2[/tex]

For ammonia gas, per one molecule of nitrogen, 2 of ammonia are produced:

[tex]10molN_2\cdot\frac{2molNH_3}{molN_2}=20molNH_3[/tex]

It means that the correct answer is N2=10; H2=30; NH3=20.

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