Answer :
[tex]P(x)=\begin{pmatrix}n \\ x\end{pmatrix}p^x(1-p)^{n-x}[/tex]
Substitute n = 5, x =2, and p = 0.712 into formula:
[tex]P(2)=0.712^2(1-0.712)^{5-2}\approx0.0121[/tex]Therefore, the