At which values of x does the function F(x) have avertical asymptote? Check all that apply.1F(x) = x(x+5)(x-1)

SOLUTION
The given fuction is:
[tex]f(x)=\frac{1}{x(x+6)(x-1)}[/tex]Note that the fuction has a vertica; asymptote when the denomiator of the function equals zero
Hence:
[tex]x(x+6)(x-1)=0[/tex]Solving the equation for x gives:
[tex]\begin{gathered} x=0,x+6=0,x-1=0 \\ x=0,x=-6,x=1 \end{gathered}[/tex]Therefore the required answer is:
[tex]x=0, x=-6, x=1[/tex]