To solve this question you need to leave in one side of the equal all the terms with the variable (x) and in the other side the other terms:
- Add x in both sides of the equation
[tex]\begin{gathered} 2x+x_{}-2=-x+x+10 \\ 3x-2=10 \end{gathered}[/tex]-Add 2 in both sides of the equation:
[tex]\begin{gathered} 3x-2+2=10+2 \\ 3x=12 \end{gathered}[/tex]-Divide into 3 both sides of the equation:
[tex]\begin{gathered} \frac{3}{3}x=\frac{12}{3} \\ \\ x=4 \end{gathered}[/tex]Then, the solution for the given equation is x=4