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as shown in the diagram below. Scalene ABFC is formed. A А B C D V E F G Which statement will allow Steve to prove ABCD || EFG? O ZCFG ~ ZFCB O ZCBFZGFC O ZABF NZBFC

Answer :

[tex]\measuredangle CFG\cong\measuredangle FCB[/tex]

because if these two angles are equal the two lines must be parallel

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