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the table below shows the probability distrubution of a random variable y y - -2 ,-1, 0,1,2,3,4 P(Y) 0.02,0.06,0.19,0.14,0.53,0.04,0.02What is the expected value of Y

Answer :

The expected value is given by:

[tex]E(Y)=\sum ^n_{i\mathop=0}y_iP(y_i)[/tex]

Therefore:

[tex]\begin{gathered} E(Y)=(-2\cdot0.02)+(-1\cdot0.06)+(0\cdot0.19)+(1\cdot0.14)+\ldots+ \\ +\cdots+(2\cdot0.53)+(3\cdot0.04)+(4\cdot0.02) \\ E(Y)=1.3 \end{gathered}[/tex]

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