Answer :
Answer:
The solution to the given quadratic equation is:
k = 17.03, -1.37
Explanation:
Given the equation:
[tex]3k^2-k-7=0[/tex]Solving this using the quadratic formula, we have:
[tex]\begin{gathered} k=\frac{-(-1)\pm\sqrt[]{(-1)^2-4(3)(-7)}_{}}{2(3)} \\ \\ =\frac{1\pm\sqrt[]{1+84}}{6} \\ \\ =\frac{1\pm\sqrt[]{85}}{6} \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} k=\frac{1+\sqrt[]{85}}{6} \\ \\ =17.03 \end{gathered}[/tex]OR
[tex]\begin{gathered} k=\frac{1-\sqrt[]{85}}{6} \\ \\ =-1.37 \end{gathered}[/tex]